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Math I Videos 77 videos

SAT Math 2.4 Algebra and Functions
186 Views

SAT Math 2.4 Algebra and Functions

Solving Proportions Using Cross Products
6802 Views

This video covers how to use cross products to solve for a missing number in a proportion by setting that proportion with a variable over the produ...

GED Math 2.4 Rational Numbers
190 Views

GED Math 2.4 Rational Numbers. Lucius's favorite restaurant is how many km from his home?

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ACT Math 2.5 Elementary Algebra 279 Views


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Description:

ACT Math Section: Elementary Algebra Drill 2, Problem 5. Use these two equations to solve for both x and y.

Language:
English Language

Transcript

00:02

Here's your shmoop du jour:

00:05

Solve for x and y: 3x + 2y = 13 6x + y = 20

00:11

And here are the potential answers...

00:20

OK. Not much of a brain-squeezer.

00:23

Since y, stands alone in the bottom equation, let's solve for y.

00:27

We get y equals 20 minus 6x.

00:30

Now we just substitute 20 minus 6x anywhere we see a y.

00:34

Ok so rewrite the above equation with that substitution and we have

00:37

3x plus 40 minus 12x equals 13

00:41

Simplify to get negative 9x equals 13 minus 40 or negative 9x equals negative 27; divide

00:48

both sides by negative 9 and we get x equals 3.

00:52

Phew. Great. Only A and B are possible answers.

00:55

Now just plug in 3 for x in the second equation

00:58

and we get 6 times 3 is 18... plus y... equals 20.

01:02

Now subtract 18 from both sides and we get y equals 2.

01:06

Here we go. So boom! The answer is B.

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